Aha! A dual: 1j1&#&.": 12345 1 2 3 4 5
The fastest expression for obtaining the decimal digits is: http://www.jsoftware.com/help/release/digits10.htm 0"."0@": 12345 1 2 3 4 5 ----- Original Message ----- From: Devon McCormick <[email protected]> Date: Friday, April 29, 2011 5:48 Subject: Re: [Jprogramming] sum of digits in a number To: Programming forum <[email protected]> > You need to turn the result back into numbers after doing the > "filled copy" > (1j1#): > > ".1j1#":12345 > 1 2 3 4 5 > +/".1j1#":12345 > 15 > > 2011/4/29 Björn Helgason <[email protected]> > > > 1j1#":12345 > > > > 2011/4/29 bill lam <[email protected]> > > > > > one way is > > > ]a=. ".,.":12345 > > > 1 2 3 4 5 > > > +/a > > > 15 > > > > > > project euler? > > > > > > Птн, 29 Апр 2011, Daniel Roe писал(а): > > > > > > > > If we add up the digits of the number 12345 we get > 1+2+3+4+5 = 15. > > > > I want to be able to do math upon the individual digits. > > > > How would I do that in J? ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
