There a few ways for you to find out: f=: 3 : 'y [ smoutput y' f^:1 2 3 ] 7 7 7 7 7 7 7
count=: 0 g=: 3 : 'y [ count=: >:count' g^:(4 1 2) 7 7 7 7 count 4 i.e. What you hoped for is true, "the second". ----- Original Message ----- From: mijj <[email protected]> Date: Monday, July 11, 2011 9:46 Subject: [Jprogramming] total number of invocations of v in v^:(1 2) To: Programming forum <[email protected]> > how many times would the verb [v] be invoked in the following: > > v^:(1 2) > > would it be: > once for the [1], and then twice for the [2]. > = 3 in total > or: > the interpreter checks the numbers for [^:] > and works to > minimise number of invocations, so makes use > of previous results. > so its once for the [1] and an additional one > for the [2] > = 2 in total. > (if that's the case, then would it still be > so if the expression > was [v^:(2 1)] ?) > ? > > i feel it's probably the first, but hope it's the second. ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
