; <@:(+/\)\. p:i.4
2 5 10 17 3 8 15 5 12 7

applies +/ on prefixes of suffixes.

Marshall

On Fri, Sep 16, 2011 at 12:59 PM, Roger Hui <[email protected]> wrote:

> Multiple applications of the infix x +/\ y does the trick.
>
>   f=: >:@i.@# +/\&.>  <
>   f 2 3 5 7
> ┌───────┬──────┬─────┬──┐
> │2 3 5 7│5 8 12│10 15│17│
> └───────┴──────┴─────┴──┘
>   g=: ;@f
>   g 2 3 5 7
> 2 3 5 7 5 8 12 10 15 17
>
> The results of f are the 1-, 2-, 3-, and 4-infix sums.
> Razing the whole thing gets the desired result.
>
>
>
> ----- Original Message -----
> From: David Vaughan <[email protected]>
> Date: Friday, September 16, 2011 9:49
> Subject: [Jprogramming] Consecutive Numbers in List
> To: Programming forum <[email protected]>
>
> > I'm trying to get a list of the sum of all possible consecutive
> > numbers.
> > E.g.
> >
> > for p:i.4, I want a list:
> >
> > 2 0 0 0
> > 2 3 0 0
> > 2 3 5 0
> > 2 3 5 7
> > 3 5 7 0
> > 5 7 0 0
> > 7 0 0 0
> > 3 5 0 0
> >
> > I then do +/"1 to get the sum of each row. My problem is that
> > I'm only getting consecutive numbers that start on p:0 or end on
> > the last value, so it misses out loads in between. In the
> > example above I get all but the last row. This is what I have so far:
> >
> >    list=:3 :'(+/"1@>{\p:i.y),+/"1@>{\.p:i.y'
> >    list 10
> > 2 5 10 17 28 41 58 77 100 129 129 127 124 119 112 101 88 71 52 29
> >
> > Also I was wondering if there was a way to streamline something
> > like that because I'm doing +/"1@>{\.p:i.y twice basically, but
> > with \. changed to \
>
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