plus`times`factorial`minus/1 2 3 4 5
-
x is: 4
y is: 5
result: _1
!
x is: 3
y is: _1
result: _1
*
x is: 2
y is: _1
result: _2
+
x is: 1
y is: _2
result: _1
_1
plus`times`factorial`minus/5 4 3 2 1
-
x is: 2
y is: 1
result: 1
!
x is: 3
y is: 1
result: 0
*
x is: 4
y is: 0
result: 0
+
x is: 5
y is: 0
result: 5
5
2012/1/3 Björn Helgason <[email protected]>
> +`*`!`-/1 2 3 4 5
> _1
> +`*`!`-/5 4 3 2 1
> 5
>
> 2012/1/3 Linda Alvord <[email protected]>
>
>> Here is another WOW !
>>
>> f=: 13 :'x*y'
>> f
>> *
>> f/1 2 3 4 5 6 7
>> 5040
>> */1 2 3 4 5 6 7
>> 5040
>> !7
>> 5040
>>
>> Sometimes the little surprises are amazing.
>>
>> Now how about Fibonacci ----
>>
>> Linda
>>
>>
>> -----Original Message-----
>> From: [email protected] [mailto:
>> [email protected]] On Behalf Of Björn Helgason
>> Sent: Tuesday, January 03, 2012 5:50 AM
>> To: Programming forum
>> Subject: Re: [Jprogramming] Binary representation without #: or #.
>>
>> f/ 5 4 3 2 1
>> x
>> 2
>> y
>> 1
>> x
>> 3
>> y
>> 2
>> x
>> 4
>> y
>> 6
>> x
>> 5
>> y
>> 24
>> 120
>>
>> 2012/1/2 Kip Murray <[email protected]>
>>
>> > Linda, Björn has a wonderful answer for your problem as I understood it.
>> > Here is another example. Suppose
>> >
>> > f =: 4 : 'x * y'
>> >
>> > Then f/ 5 4 3 2 1 is 5 f 4 f 3 f 2 f 1 so
>> >
>> >
>> ----------------------------------------------------------------------
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>>
>> ----------------------------------------------------------------------
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>>
>
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