> I have to admit I overlooked /. . I will carefully go through the
> entire dictionary once more.
> Yeah, the empty slot... I could find a workaround, but a solution that
> takes it into account will still be appreciated.
I'd build a boolean argumento to #^:_1 (APL's expand) by starting from
2 -~/\ ~._1,0{a
which identifies the skip in the sequence. Of course, if the skip is >1 (you
left out the 3 in your example, but you could have left out 3 AND 4, in
which case you'd need two empty boxes). I put together this:
(;(2 -~/\ ~._1,0{a)|.@{. each 1) #^:_1 </./a
----T-------T---------TT-----T---┐
│5 0│7 8 9 2│2 5 5 5 3││8 0 0│5 6│
L---+-------+---------++-----+----
which seems to work (but may very well be wrong, and is not very elegant
because of the "each").
--
Stefano
[ "There are some people who, if they don't already know, you can't tell
'em." --- Yogi Berra ]
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