That's v/x1,x2,y .  Depending on what x1, x2, and y are you may have to do
> v&.>/ x1;x2;y .



On Wed, Jan 11, 2012 at 12:24 PM, David Ward Lambert <b49p23t...@stny.rr.com
> wrote:

> I've run into a particular pattern several times recently.  Have I
> overlooked a shorthand to use v repeatedly with several values of x?
>
>   x1 v x2 v y
>
> Oh hang on, maybe I want the iteration feature of bond I've never before
> used.  No.  That looks different.
>
> Thank you, Dave.
>
>
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