That's v/x1,x2,y . Depending on what x1, x2, and y are you may have to do > v&.>/ x1;x2;y .
On Wed, Jan 11, 2012 at 12:24 PM, David Ward Lambert <b49p23t...@stny.rr.com > wrote: > I've run into a particular pattern several times recently. Have I > overlooked a shorthand to use v repeatedly with several values of x? > > x1 v x2 v y > > Oh hang on, maybe I want the iteration feature of bond I've never before > used. No. That looks different. > > Thank you, Dave. > > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm