Where is this help, where sj and mj are defined?
Henry Rich
On 2/24/2012 7:25 PM, Don Guinn wrote:
> I've lost track of the number of times I have tried to make dyadic ;: work.
> I read it, understand it (I think), but I can't get it to work. The general
> description has m, the input mapping as a list of boxes, each box
> containing the items to be mapped to the same number. So, in an attempt to
> figure out what is going on I converted the example in help to that form
> and get an error.
>
> Given sj, mj and y as defined in help:
>
> (0;sj;mj) ;: y
> +---+--+-+--+---+-+-+-+-+-+---+-+---+-+
> |sum|=.|(|i.|3 4|)|+|/|.|*|0j4|+|pru|4|
> +---+--+-+--+---+-+-+-+-+-+---+-+---+-+
>
> So far, so good. Convert mj to the boxed form (display shortened to fit
> e-mail):
>
> mj2=:(/:~.mj){mj</.a.
> ,.50{.&.>mj2
> +--------------------------------------------------+
> | ┌┬┐├┼┤└┴┘│─ !"#$%&()*+,-/;<=>?@|
> +--------------------------------------------------+
> | |
> +--------------------------------------------------+
> |ACDEFGHIJKLMOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz|
> +--------------------------------------------------+
> |N |
> +--------------------------------------------------+
> |B |
> +--------------------------------------------------+
> |0123456789_ |
> +--------------------------------------------------+
> |. |
> +--------------------------------------------------+
> |: |
> +--------------------------------------------------+
> |' |
> +--------------------------------------------------+
>
> Test it to see if it is ok.
>
> my=. (y i.~;m) { (#m),~(#&>m)#i.#m NB. From help
> y,:,":"0 my
> sum=. (i.3 4)+/ .*0j4+pru 4
> 222061026515000160525022215
>
> Looks good, but
>
> (0;sj;mj2) ;: y
> |length error
> | (0;sj;mj2) ;:y
>
> The problem is not with y, but something about mj2.
>
> (0;sj;mj2)&;:
> |length error
> | (0;sj;mj2)&;:
>
> As I understand the description in help, this should work.
>
> So, what am I missing?
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