2012/4/4 Jose Mario Quintana <[email protected]> > They both know that there is precisely 0^0 function with the empty set as > its domain and codomain. >
The empties do not behave the same
0^0
1
a:=''
a:=i.0
(i.0)^i.0
('')^('')
0%0
0
0%i.0
(i.0)%i.0
(a:)%(a:)
|domain error
| (a:) %(a:)
(i.0)^''
a:-:i.0
0
(a:) ^(a:)
|domain error
| (a:) ^(a:)
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