On Mon, Jun 18, 2012 at 9:15 PM, Gian Medri <gianme...@gmail.com> wrote:
> Hi!
>
> I shall replace some text in a vector. My function is
> Replace=:13 :'(p{.y),(>1{x),(($>0{x)+p=.I. (>0{x) E. y)}.y'
> Example : ('can be';'is') Replace 'Life can be good'
> Life is good
> I would like to see if there is a better solution, more J-like.
>
I'm not sure what the desired behaviour for Replace is for strings
where the text to be replaced doesn't occur or occurs more than once
but if you're wanting an explicit version of that code then here is
one:
Replace2=: (] {.~ 0&{::@[ I.@E. ]) , 1&{::@[ , ] }.~ #@(0&{::)@[ +
0&{::@[ I.@E. ]
('can be';'is') Replace2 'Life can be good'
Life is good
However, for something like that I'd tend to move to an explicit
definition. Something like the following will handle most edge cases
nicely as well as being easier to maintain.
replace3=: 4 : 0
'findtxt repltxt'=. boxopen x
out=. findtxt (] <;.1~ (1:)`(I.@E.)`(0 #~ #@])}) findtxt,y
out=. (#repltxt)}. ; (repltxt , (#findtxt)&}.) &.> out
)
The second line boxes the initial string wherever the findtxt begins.
The 3rd line then drops the findtxt from each box and catenates the
repltxt
If you are wanting to do this routinely though then I'd suggest using
the base library verbs
stringreplace or rplc which also handle multiple find/replace pairs.
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