Nice explanation of summaries here:
https://grafana.com/blog/2022/03/01/how-summary-metrics-work-in-prometheus/

On Monday, 23 June 2025 at 12:42:35 UTC+1 Brian Candler wrote:

> Remember that histograms don't store values. All they do is increment a 
> counter by 1; the value is only used to select which bucket to increment.  
> This means that the amount of storage used by a histogram is very small - a 
> fixed number of buckets with one counter each. It doesn't matter if you are 
> processing 1 sample per second or 10,000 samples per second.
>
> If you wanted to retrieve the *exact* lowest or highest value, over *any* 
> arbitrary time period that you query, you would have to store every single 
> value into a database. Prometheus is not a event logging system, and it 
> will never work this way. A columnar datastore like Clickhouse can do that 
> quite well, but if the number of samples is large, you will still have a 
> very large storage issue.
>
> More realistically, you could find the minimum or maximum value seen over 
> a fixed time period (say one minute), and at the end of that minute, export 
> the min/max value seen. That's cheap and quick. Indeed, you could do it 
> over a relatively short time period (e.g. 1 second), and use prometheus' 
> min/max_over_time functions if you want to query a longer period, i.e. to 
> find the min of the mins, or the max of the maxes.  You need to make sure 
> that every distinct min/max value ends up in the database though; either 
> use remote_write to push them, or scrape your exporter at least twice as 
> fast as the min/max values are changing.
>
> In my experience, people are often not so interested in the single minimum 
> or maximum value, but in the quantiles, such as the 1st percentile ("the 
> fastest 1% of queries were answered in less than X seconds") or the 99th 
> percentile ("the slowest 1% of queries were answered in more than Y 
> seconds"). Prometheus can help you using a data type called a "summary":
> https://prometheus.io/docs/concepts/metric_types/#summary
> https://prometheus.io/docs/practices/histograms/#quantiles
>
> A summary can give you very good estimates of the percentiles over a 
> sliding time window (of a size you have to choose in advance), and uses a 
> relatively small amount of storage like a histogram. It is better than a 
> histogram in the case where you don't know in advance what the highest and 
> lowest values are likely to be (i.e. you don't need to pre-allocate your 
> bucket boundaries correctly).
>
> On Monday, 23 June 2025 at 08:15:42 UTC+1 tejaswini vadlamudi wrote:
>
>> Thanks Brain, for the clear heads-up and explanation!
>>
>> It looks to me that there is no possibility to secure exact maximum and 
>> exact minimum values for durations (based on Prometheus histograms) :-(
>>
>> However, for performing exploratory data analysis on the application 
>> software, need this summary statistics information, such as minimum and 
>> maximum values. Legacy monitoring systems have always had this support, 
>> which in turn expects the new technology to fit the use case to ensure 
>> backward compatibility. 
>>
>> Please share what can be done in this regard to secure this info.
>>
>> I'm thinking out loud, please correct/add wherever possible:
>>
>> 1. Does changing from Prometheus to OTEL instrumentation provide this 
>> feature (exact max and min duration time)?
>> 2. Can metrics derived from distributed traces (instrumented with 
>> OTEL/Jaeger) be used to obtain minimum and maximum request durations?
>> 3. Is it possible to secure the max and min duration time with Prometheus 
>> with any hack?
>>       a. For Classic Histograms?
>>       b. For Native Histograms?
>> 4. A new PR/contribution on Prometheus to offer this support?
>>
>> Thanks,
>> Teja
>>
>> On Thursday, June 19, 2025 at 6:38:59 PM UTC+2 Brian Candler wrote:
>>
>>> In general, I don't think you can get an accurate answer to that 
>>> question from a histogram.
>>>
>>> You can work out which *bucket* the lowest and highest request durations 
>>> sat in, which means you could give the lower and upper bounds of the 
>>> minimum, and the lower and upper bounds of the maximum. Just compare the 
>>> bucket counters at the start and end of the time range, and find the lowest 
>>> boundary (le) which has changed, and the highest boundary which has 
>>> changed. But this still doesn't tell you what the *actual* value was.  
>>>
>>> I don't think there's any point in trying to make an estimate of the 
>>> actual value; these values are, by definition, outliers, so even if your 
>>> data points fitted a nice distribution, these ones would be at the ends of 
>>> the curve and subject to high error.
>>>
>>> Your LLM answer is essentially what it says in the documentation 
>>> <https://prometheus.io/docs/prometheus/latest/querying/functions/#histogram_quantile>
>>>  
>>> for histogram_quantile:
>>>
>>> *You can use histogram_quantile(0, v instant-vector) to get the 
>>> estimated minimum value stored in a histogram.*
>>>
>>> *You can use histogram_quantile(1, v instant-vector) to get the 
>>> estimated maximum value stored in a histogram.*
>>> I thought it was worth testing. Here is a metric from my home prometheus 
>>> server, running 2.53.4:
>>>
>>> *go_gc_pauses_seconds_bucket*
>>> =>
>>> go_gc_pauses_seconds_bucket{instance="localhost:9090", job="prometheus", 
>>> le="6.399999999999999e-08"} 0
>>> go_gc_pauses_seconds_bucket{instance="localhost:9090", job="prometheus", 
>>> le="6.399999999999999e-07"} 0
>>> go_gc_pauses_seconds_bucket{instance="localhost:9090", job="prometheus", 
>>> le="7.167999999999999e-06"} 12193
>>> go_gc_pauses_seconds_bucket{instance="localhost:9090", job="prometheus", 
>>> le="8.191999999999999e-05"} 15369
>>> go_gc_pauses_seconds_bucket{instance="localhost:9090", job="prometheus", 
>>> le="0.0009175039999999999"} 27038
>>> go_gc_pauses_seconds_bucket{instance="localhost:9090", job="prometheus", 
>>> le="0.010485759999999998"} 27085
>>> go_gc_pauses_seconds_bucket{instance="localhost:9090", job="prometheus", 
>>> le="0.11744051199999998"} 27086
>>> go_gc_pauses_seconds_bucket{instance="localhost:9090", job="prometheus", 
>>> le="+Inf"} 27086
>>>
>>> *go_gc_pauses_seconds_bucket - go_gc_pauses_seconds_bucket offset 10m*
>>> =>
>>> {instance="localhost:9090", job="prometheus", 
>>> le="6.399999999999999e-08"} 0
>>> {instance="localhost:9090", job="prometheus", 
>>> le="6.399999999999999e-07"} 0
>>> {instance="localhost:9090", job="prometheus", 
>>> le="7.167999999999999e-06"} 5
>>> {instance="localhost:9090", job="prometheus", 
>>> le="8.191999999999999e-05"} 5
>>> {instance="localhost:9090", job="prometheus", 
>>> le="0.0009175039999999999"} 10
>>> {instance="localhost:9090", job="prometheus", le="0.010485759999999998"} 
>>> 10
>>> {instance="localhost:9090", job="prometheus", le="0.11744051199999998"} 
>>> 10
>>> {instance="localhost:9090", job="prometheus", le="+Inf"} 10
>>>
>>> *rate(go_gc_pauses_seconds_bucket[10m])*
>>> =>
>>> {instance="localhost:9090", job="prometheus", 
>>> le="6.399999999999999e-08"} 0
>>> {instance="localhost:9090", job="prometheus", 
>>> le="6.399999999999999e-07"} 0
>>> {instance="localhost:9090", job="prometheus", 
>>> le="7.167999999999999e-06"} 0.007407407407407408
>>> {instance="localhost:9090", job="prometheus", 
>>> le="8.191999999999999e-05"} 0.007407407407407408
>>> {instance="localhost:9090", job="prometheus", 
>>> le="0.0009175039999999999"} 0.014814814814814815
>>> {instance="localhost:9090", job="prometheus", le="0.010485759999999998"} 
>>> 0.014814814814814815
>>> {instance="localhost:9090", job="prometheus", le="0.11744051199999998"} 
>>> 0.014814814814814815
>>> {instance="localhost:9090", job="prometheus", le="+Inf"} 
>>> 0.014814814814814815
>>>
>>> Those exponential bucket boundaries in scientific notation aren't very 
>>> readable, but you can see that:
>>> * the lowest response time must have been somewhere 
>>> between 6.399999999999999e-07 and 7.167999999999999e-06
>>> * the highest response time must have been somewhere between 
>>> 8.191999999999999e-05 and 0.0009175039999999999
>>>  
>>> Here are the answers from the formula the LLM suggested:
>>>
>>>
>>> *histogram_quantile(0, rate(go_gc_pauses_seconds_bucket[10m]))*=>
>>> {instance="localhost:9090", job="prometheus"} *NaN*
>>>
>>> *histogram_quantile(1, rate(go_gc_pauses_seconds_bucket[10m]))*
>>> =>
>>> {instance="localhost:9090", job="prometheus"} *0.0009175039999999999*
>>>
>>> The lower boundary of "NaN" is not useful at all (possibly this is a 
>>> bug?), but I found I could get a value by specifying a very low, but 
>>> non-zero, quantile:
>>>
>>>
>>> *histogram_quantile(0.000000001, rate(go_gc_pauses_seconds_bucket[10m]))*
>>> =>
>>> {instance="localhost:9090", job="prometheus"} *6.40000013056e-07*
>>>
>>> Those values *do* sit between the boundaries given:
>>>
>>> >>> 6.399999999999999e-07 < 6.40000013056e-07 <= 7.167999999999999e-06
>>> True
>>> >>> 8.191999999999999e-05 < 0.0009175039999999999 <= 
>>> 0.0009175039999999999
>>> True
>>>
>>> In fact, the "minimum" answer is very close to the lower edge of the 
>>> relevant bucket, and the "maximum" is the upper edge of the relevant bucket.
>>>
>>> Therefore, these are not the *actual* minimum and maximum request times. 
>>> In effect, they are saying "the minimum request time was *more than* 
>>> 6.399999999999999e-07, 
>>> and the maximum request time was *no more than* 
>>> 0.0009175039999999999".  But that's as good as you can get with a histogram.
>>>
>>> On Wednesday, 18 June 2025 at 18:17:15 UTC+1 tejaswini vadlamudi wrote:
>>>
>>>> Including answer from Gen-AI:
>>>>
>>>> | Description                         | PromQL Query                   
>>>>                                                                            
>>>>  
>>>>       | Notes                                                              
>>>>  
>>>>                             |
>>>>
>>>> |-------------------------------------|------------------------------------------------------------------------------------------------------------------|--------------------------------------------------------------------------------------------------|
>>>> | Minimum request duration (1m)       | histogram_quantile(0, sum by 
>>>> (le) (rate(http_request_duration_seconds_bucket[1m])))                     
>>>>         | Fast but may be noisy or return NaN if low traffic. Good for 
>>>> near-real-time.                   |
>>>> | Maximum request duration (1m)       | histogram_quantile(1, sum by 
>>>> (le) (rate(http_request_duration_seconds_bucket[1m])))                     
>>>>         | Same as above, for longest duration estimate.                    
>>>>  
>>>>                               |
>>>> | Minimum request duration (5m)       | histogram_quantile(0, sum by 
>>>> (le) (rate(http_request_duration_seconds_bucket[5m])))                     
>>>>         | More stable, smoother estimate over a slightly longer window.    
>>>>  
>>>>                               |
>>>> | Maximum request duration (5m)       | histogram_quantile(1, sum by 
>>>> (le) (rate(http_request_duration_seconds_bucket[5m])))                     
>>>>         | Recommended when traffic is bursty or histogram series are 
>>>> sparse.                             |
>>>>
>>>> Please confirm if the above answer is reliable or not. 
>>>> On Wednesday, June 18, 2025 at 3:23:54 PM UTC+2 tejaswini vadlamudi 
>>>> wrote:
>>>>
>>>>> Hi,
>>>>>
>>>>> I’m using Prometheus to monitor request durations via a histogram 
>>>>> metric, e.g., http_request_duration_seconds_bucket. I would like to 
>>>>> query:
>>>>>
>>>>>    - The minimum time taken by a request
>>>>>    - The maximum time taken by a request
>>>>>
>>>>> …over a given time range (say, the last 1h or 24h).
>>>>>
>>>>> I understand that histogram buckets give cumulative counts of requests 
>>>>> below certain durations, but I’m not sure how to extract the actual min 
>>>>> or 
>>>>> max values of request durations during a time window.
>>>>>
>>>>> Is this possible directly via PromQL? Or is there a recommended 
>>>>> workaround (e.g., recording rules, external processing, or using 
>>>>> histogram_quantile() in a specific way)?
>>>>>
>>>>> Thanks in advance for any guidance!
>>>>>
>>>>> Br,
>>>>> Teja
>>>>>
>>>>

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