On 12/8/2010 5:30 PM, Thomas Heller wrote:
> I don't really now how to do it otherwise with the current design.
> There is really only this part of the puzzle missing. If it is done, we have
> a working and clean Phoenix V3.
> For the time being, I can live with the workaround I did.
> However, I will focus my efforts of the next days on working out a patch for
> this to work properly.
I made a simple fix to proto::matches on trunk that should get you
moving. The overloads can still be smarter about sub-domains, but for
now you can easily work around that by explicitly allowing expressions
in sub-domains in your super-domain's grammar. See the attached solution
to your original problem.
--
Eric Niebler
BoostPro Computing
http://www.boostpro.com
#include <boost/proto/proto.hpp>
namespace mpl = boost::mpl;
namespace proto = boost::proto;
typedef proto::terminal<int> int_terminal;
typedef proto::terminal<double> double_terminal;
template <typename Expr>
struct actor1;
struct domain1;
struct grammar1
: proto::or_<
proto::plus<grammar1, grammar1>
, int_terminal
, proto::if_<proto::is_sub_domain_of<proto::domain_of<proto::_>,
domain1>()>
>
{};
struct domain1
: proto::domain<
proto::pod_generator<actor1>
, grammar1
, proto::default_domain
>
{};
template <typename Expr>
struct actor1
{
BOOST_PROTO_BASIC_EXTENDS(Expr, actor1<Expr>, domain1)
};
template <typename Expr>
struct actor2;
struct grammar2
: proto::or_<
proto::plus<grammar2, grammar2>
, double_terminal
>
{};
struct domain2
: proto::domain<
proto::pod_generator<actor2>
, grammar2
, domain1
>
{};
template <typename Expr>
struct actor2
{
BOOST_PROTO_BASIC_EXTENDS(Expr, actor2<Expr>, domain2)
};
actor1<int_terminal::type> t1 = {{0}};
actor2<double_terminal::type> t2 = {{0}};
int main()
{
t1;
t1 + t1;
t2;
t2 + t2;
t1 + t2;
}
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