HI all
On Sun, Jun 12, 2011 at 11:58 PM, Kavi <targetn...@gmail.com> wrote: > I have this simple .proto file: > > package test; > > message Person { > required string name = 1; > required int32 age = 2; > } > > I have this test file to write contents: > > #include <iostream> > #include <fstream> > #include <string> > #include "test.pb.h" > #include <stdio.h> > using namespace std; > > int main(){ > > string data,dummy; > test::Person kavi; > kavi.set_name("Kavi"); > kavi.set_age(22); > ofstream out; > out.open("data.dat"); > > > kavi.SerializeToString(&data); > out<<data<<endl; > out.close(); > > ifstream in; > in.open("data.dat"); > in>>dummy; > cout<<dummy<<endl; > cout<<data<<endl; > > test::Person second; > second.ParseFromString(data); > cout<<second.name(); > cout<<"\n"; > cout<<second.age(); > in.close(); > > > return 0; > } > > When I tried to compile this, it works fine. But when I change the > line second.ParseFromString(data) to second.ParseFromString(dummy), it > compiles fine and on executing, it throws the following error: > > "libprotobuf ERROR google/protobuf/message_lite.cc:123] Can't parse > message of type "test.Person" because it is missing required fields: > name, age" > > Basically the strings dummy and data are the same. So why does it > throw the error?? Somebody please suggest a fix. > > Thanks in advance, > Kavi > > -- > You received this message because you are subscribed to the Google Groups > "Protocol Buffers" group. > To post to this group, send email to protobuf@googlegroups.com. > To unsubscribe from this group, send email to > protobuf+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/protobuf?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Protocol Buffers" group. To post to this group, send email to protobuf@googlegroups.com. To unsubscribe from this group, send email to protobuf+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/protobuf?hl=en.