Updates:
Status: WorkingAsIntended
Owner: xiaof...@google.com
Comment #1 on issue 674 by xiaof...@google.com: protoc: can't control
output directory
https://code.google.com/p/protobuf/issues/detail?id=674
Here is how it works:
Support you invoke protoc as:
protoc -Ipath1 --cpp_out=path2 path1/path3/test.proto
protoc will generate:
path2/path3/test.pb.h
path2/path3/test.pb.cc
The canonical name of the .proto file will be "path3/test.proto" and that's
the name used to refer to this file in protobuf runtime (e.g., you need to
use this name in DescriptorPool::FindFileByName()).
We should document this better but this is working as intended.
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