Jie Liu responded to Tunc Simsek's questions, but his response to ptolemy-hackers bounced because of a configuration issue. -Christopher
> Hi Tunc, > At 11:04 AM 1/14/2002 -0800, Christopher Hylands wrote: > These two questions from Tunc appeared in comp.soft-sys.ptolemy > Offhand, I don't have answers to his questions. > If you have a response, please cc > [EMAIL PROTECTED] > -Christopher > > From: Tunc Simsek <[EMAIL PROTECTED]> > > Subject: ct step input > > Date: Fri, 11 Jan 2002 15:44:32 -0800 > > > > is there an actor for a step source in CT domain? > > I tried pulse but that doesn't take real indices. > > > > -- Tunc > In CT, you use the Clock actor for step functions. In fact, > it is a square wave function. To get a step function, set > the period to be larger than the stop time, or set it to 0. > > > > From: Tunc Simsek <[EMAIL PROTECTED]> > > Subject: matrices > > Date: Fri, 11 Jan 2002 17:39:32 -0800 > > > > Is it possible to implement in CT domain the equation > > > > x' = Ax > > > > where A=[-1 1; 0 -1], x0=[1,1]' > > > > and then extract (I guess using vector dissassembler) x_1 and x_2. > > > > If so, could someone please send me the xml file with this model in > > it. > > > > Thanks again, > > Tunc > Isn't states in a system are supposed to be hidden from the output? > Why don't you build a state observer? :-) > Actually, the LinearStateSpace actor didn't have a state output, so > you can't get them as an output of the actor. I just added the port > called stateOutput. It is a multi-port, so the first link connected > to it wi receive x_1, the second is x_2, etc. No vector assembler/ > disassembler are needed, since the internal of the LinearStateSpace > actor does not use a vector representation. To get the new actor, > you need to update the tree. > Hope it helps. > Jie ---------------------------------------------------------------------------- Posted to the ptolemy-hackers mailing list. Please send administrative mail for this list to: [EMAIL PROTECTED]
