Google helped me get stared and I did something like this:
if n1 == (n2 * 2)
# do this
elsif n1 == n2
# do that
end
which appears to be working. Is "then" optional? cheers!!
On Jun 14, 3:41 pm, Ken Barber <k...@puppetlabs.com> wrote:
> ruby != bash :-). You need a ruby book if you can :-).
>
> if n1 == n2 then
> # do something
> elsif n2 == n1*2 then
> # do something else
> end
>
> ken.
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