Because the name depends on other parameters in a non-trivial way.
But that's neither here nor there. remeber the context:
We were talking about parser v compiler error reporting.
--
vagn
On 07/04/2011 11:53 PM, Scott Smith wrote:
Why would you pass the output from inline_template as the title of a
resource?
On Mon, Jul 4, 2011 at 8:03 PM, vagn scott <vagnsc...@gmail.com
<mailto:vagnsc...@gmail.com>> wrote:
$foo = inline_template( ... )
$baz = inline_template( ... )
File[ "$foo$baz" ]
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