Because the name depends on other parameters in a non-trivial way.
But that's neither here nor there.  remeber the context:
We were talking about parser v compiler error reporting.

--
vagn

On 07/04/2011 11:53 PM, Scott Smith wrote:
Why would you pass the output from inline_template as the title of a resource?

On Mon, Jul 4, 2011 at 8:03 PM, vagn scott <vagnsc...@gmail.com <mailto:vagnsc...@gmail.com>> wrote:


           $foo = inline_template( ... )
           $baz = inline_template( ... )
           File[ "$foo$baz" ]


--
You received this message because you are subscribed to the Google Groups "Puppet 
Users" group.
To post to this group, send email to puppet-users@googlegroups.com.
To unsubscribe from this group, send email to 
puppet-users+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/puppet-users?hl=en.

Reply via email to