+1 on that. exec a shell command.
Look at it this way: How can you get the list of files without running a shell
command ?
Short answer: You cannot, so make it a chmod instead of an ls command and you
are done.
“Sometimes I think the surest sign that intelligent life exists elsewhere in
the universe is that none of it has tried to contact us.”
Bill Waterson (Calvin & Hobbes)
----- Original Message -----
From: "jcbollinger" <john.bollin...@stjude.org>
To: puppet-users@googlegroups.com
Sent: Friday, August 2, 2013 9:03:21 AM
Subject: [Puppet Users] Re: Wildcards in file resourses -- yet another time
On Friday, August 2, 2013 3:39:32 AM UTC-5, Ivan Lysov wrote:
Hi All!
I want to grant spetial permissions on some core files. So it would be nice to
use something like
file { "/var/lib/monitorium/core*" :
mode => 0644,
}
But that obviously doesn't work. Any people with the same problem i've googled
used some workarounds like managing directories recursively or writing more
complicated scripts.
I can't manage the whole directory because of many other files inside and i
don't want to extrabloat my manifests.
What should i do?
If you imagine declaring a single resource of a built-in type that encompasses
multiple files inside a given directory, then that can only be structured as a
recursive File resource aimed at the directory. Non-recursive Files always
represent exactly one file / directory / symlink.
Unfortunately, however, Puppet does not support what you are asking. The
'ignore' parameter is as close as it comes: with that you could manage all
files in a given directory except those matching some glob, but you want the
opposite selection criterion.
As far as I can see, your best bet for a Puppet-based solution is an Exec.
John
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