I got pycuda working Vista x64 machine with python 2.6, but the platform_bits
method in tools.py is not working for me. It returns 32 on my 64 bit
platform, which is causing test_driver.py to fail.
The error I am getting is the following:
C:\Python26\lib\site-packages\pycuda-0.94beta-py2.6-win-amd64.egg\pycuda\tools.py:343:
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
_ _
dtype = dtype('uint64'), with_fp_tex_hack = False
def dtype_to_ctype(dtype, with_fp_tex_hack=False):
if dtype is None:
raise ValueError("dtype may not be None")
import numpy
dtype = numpy.dtype(dtype)
if dtype == numpy.int64 and platform_bits() == 64:
return "long"
elif dtype == numpy.uint64 and platform_bits() == 64:
return "unsigned long"
elif dtype == numpy.int32:
return "int"
elif dtype == numpy.uint32:
return "unsigned int"
elif dtype == numpy.int16:
return "short int"
elif dtype == numpy.uint16:
return "short unsigned int"
elif dtype == numpy.int8:
return "signed char"
elif dtype == numpy.uint8:
return "unsigned char"
elif dtype == numpy.float32:
if with_fp_tex_hack:
return "fp_tex_float"
else:
return "float"
elif dtype == numpy.float64:
if with_fp_tex_hack:
return "fp_tex_double"
else:
return "double"
else:
> raise ValueError, "unable to map dtype '%s'" % dtype
E ValueError: unable to map dtype 'uint64'
May I suggest an alternate implementation to this (platform_bits1):
Python 2.6.2 (r262:71605, Apr 14 2009, 22:46:50) [MSC v.1500 64 bit (AMD64)]
on
win32
Type "help", "copyright", "credits" or "license" for more information.
>>> def platform_bits():
... from struct import calcsize
... return calcsize('l') * 8
...
>>> print platform_bits()
32
>>> def platform_bits1():
... return tuple.__itemsize__ * 8
...
>>> print platform_bits1()
64
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