On Tue, Nov 16, 2010 at 9:33 PM, Cyrus Omar <cy...@cmu.edu> wrote: > On Tue, Nov 16, 2010 at 20:25, Dan Goodman <dg.pyc...@thesamovar.net>wrote: > >> A final option that I thought of would be to check for a launch timeout >> failure after each kernel launch, and if it happens, divide my problem size >> by two and try again, repeating until I don't get any launch failures. The >> trouble with this approach is that I'll get multiple failures and screen >> flashes before it settles down to a value that works, wasting a little bit >> of time but more importantly being quite alarming. It also doesn't feel very >> elegant... ;-) > > > This is risky, as per the TDR webpage you linked to: >
Why not starting with a small size and if it take less then half of 2 or 5 seconds depending of the os, you double the size for the next time? Fred
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