Hi! I think he meant to take the square root. That would be the distance, which is the vector result of a 3 dimensional image...
DR0ID wrote: > Hi > >> def CalculateDistance(a, b): >> x, y, z = b[0] - a[0], b[1] - a[1], b[2] - a[2] >> dist = x*x + y*y + z*z >> return dist * dist >> > > no offense, but "x*x + y*y + z*z" is already the distance squared, so > no need for "return dist*dist". (or did you do this on purpose?). > > ~DR0ID > > Uh, yeah, good catch. :-)