class compile? Anyway, does it effectively work that way?
--- On Wed, 12/31/08, Noah Kantrowitz <n...@coderanger.net> wrote: From: Noah Kantrowitz <n...@coderanger.net> Subject: Re: [pygame] @ To: pygame-users@seul.org Date: Wednesday, December 31, 2008, 1:41 PM No, i has nothing to do with runtime. Decorators are evaluated during class compile. --Noah On Dec 31, 2008, at 12:05 PM, Yanom Mobis wrote: > Ohhhh! I get it now! It's used to insure that a specific function > is always called before another. Thanks for clearing it up for me.. > --- On Wed, 12/31/08, Michael Phipps <michael.phi...@bluetie.com> > wrote: > > From: Michael Phipps <michael.phi...@bluetie.com> > Subject: Re: [pygame] @ > To: pygame-users@seul.org > Date: Wednesday, December 31, 2008, 4:37 PM > > Yanom - > > A decorator is a method that takes another method as a parameter so > that it can do something.. It is usually used for aspect oriented > programming. > > For example: > > def logThisMethodCall(methodCall) > # Do some logging here > > @logThisMethodCall > def myMethod(a,b,c) > # do Somthing in here > > Now, whenever you call "myMethod", logThisMethodCall gets called > first, with the invocation of myMethod passed into it. You can use > it for logging, security (i.e. does this person have permission to > be calling this), etc. > > Michael > > > > > -----Original Message----- > From: "Yanom Mobis" [ya...@rocketmail.com] > Date: 12/31/2008 11:19 > To: pygame-users@seul.org > Subject: Re: [pygame] @ > > so when you do this: > > @foo > def bar(): pass > > you assume that a function foo() already exists. > > and it creates something like this: > > def foo(): > def bar(): pass > pass > > ? > I'm sorry, I just got confused. > > > > > - On Wed, 12/31/08, Noah Kantrowitz <n...@coderanger.net> wrote: > From: Noah Kantrowitz <n...@coderanger.net> > Subject: Re: [pygame] @ > To: pygame-users@seul.org > Date: Wednesday, December 31, 2008, 3:01 AM > > decorator. The short version is that this > > @foo > def bar(): pass > > is the same as this > > def bar(): pass > bar = foo(bar) > > The long version is "look it up because it gets very complicated and > voodoo-ish" > > --Noah > > On Dec 30, 2008, at 9:55 PM, Yanom Mobis wrote: > >> I was reading some Python code examples, and i found the @ symbol. >> What > exactly does this operator do? >> > > > > > > > > > > > >
