On Sat, Nov 29, 2008 at 8:24 PM, Alex Holkner <[EMAIL PROTECTED]>wrote:

> You just need to schedule your update function on the clock (instead
> of in the draw method):
>
> def update(dt):
>    ship.update()
>
> period = 1 / 60.0 # 60 frames per second
> pyglet.clock.schedule_interval(update, period)
>
> Alex.


I am curious as to whether this actually guarantees that the window is
redrawn once per update. In particular, what happens if multiple intervals
are scheduled on the clock? Does the window get redrawn according to the
shortest interval, or every time an interval expires?

- Tristam

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