Uh, wait. You're sending the song name to a socket, then playing the music.
Why send the song name?
Brutish solution is this:
def update(dt):
global music
if not music.playing:
pyglet.app.exit()
and before pyglet.app.run():
pyglet.clock.schedule_interval(1/60.0, update)
This should work. For reference, check the documentation on music playback
and event loops. API reference could also help.
On 18 July 2011 17:40, musicmac <[email protected]> wrote:
> hey guys
> i just started using pyglet this morning for a music project, the idea
> is to be able to play the same song on 2 machines much like a sonos
> box or something but the cheap man way. I currently have
> [code]
> import os
> import socket
> import pyglet
>
> port = 8081
> s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
> print 'ip adress?'
> ip = raw_input();
> dir = os.getcwd()
> print os.listdir(dir)
> running = 1
> while (running == 1):
> print "which song now? (type the file name in full don't forget
> the .mp3)"
> song = raw_input()
> s.sendto((song), (ip, port))
> music = pyglet.resource.media(song)
> music.play()
> pyglet.app.run()
> [/code]
> but the program just sticks at playing the song and pyglet won't
> close :(
> TLDR how can i close pyglet after a song has played?
>
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