I was able to get it to work with pylget.app.run() by adding
self.dispatch_event('on_draw') to the toggle method in my window class. Is
this the proper approach?
On Friday, December 9, 2016 at 10:13:51 AM UTC-5, Gregory Howland wrote:
>
> Hi. I'm new to pyglet and having a little difficulty understanding how
> pyglet.app.run() updates multiple windows, particularly windows that are
> not the active window.
>
> I am trying to write a simple program that does the following.
>
> 1. Creates 2 windows that are initially colored all white.
> 2. If the user presses the key "1", it should toggle the first window
> between white and black and print "1" to the console.
> 3. If the user presses the key "2", it should toggle the second window
> between white and black and print "2" to the console
>
> The toggling behavior should occur for either window regardless of what
> window is active (i.e., if window 1 is active and the user presses "2", the
> color of window 2 should toggle)
>
> import pyglet
> from pyglet.window import key
> from pyglet.gl import *
>
> class ToggleWindow(pyglet.window.Window):
>
> def __init__(self):
> super(ToggleWindow, self).__init__()
> self.color = 1.0
>
> def toggle(self):
> if self.color == 1.0:
> self.color = 0.0
> else:
> self.color = 1.0
>
> def on_draw(self):
> self.switch_to()
>
> glClear(GL_COLOR_BUFFER_BIT)
> glLoadIdentity()
> glColor3f(self.color,self.color,self.color)
> glBegin(GL_QUADS)
> glVertex2f(0,0)
> glVertex2f(self.width,0)
> glVertex2f(self.width,self.height)
> glVertex2f(0,self.height)
> glEnd()
>
> def main():
>
> window1 = ToggleWindow()
> window2 = ToggleWindow()
>
> @window1.event
> @window2.event
> def on_key_press(symbol, modifiers):
> if symbol == key._1:
> print(1)
> window1.toggle()
> elif symbol == key._2:
> print(2)
> window2.toggle()
> else:
> print(symbol)
>
> pyglet.app.run()
>
>
> if __name__ == "__main__":
> main()
>
>
> The problem is that only the active window color will toggle. Is there
> some event I have to dispatch to get the render loop to redraw an inactive
> window? I thought maybe the "switch_to()" method would do this but I guess
> it only changes the opengl context?
>
> I can get the program to work as intended if I replace pyglet.app.run()
> with a manual render loop like I might do in SDL, but this is obviously the
> sort of thing pyglet is designed to avoid.
>
> while True:
> pyglet.clock.tick()
>
> for window in pyglet.app.windows:
> window.switch_to()
> window.dispatch_events()
> window.dispatch_event('on_draw')
> window.flip()
>
>
>
> Any thoughts? I am on linux if it is relevant.
>
> Thanks in advance for any help.
>
>
>
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