John Ehresman wrote:
Gonzalo Aguilar Delgado wrote:
How do I find a widget (say a GtkEntry) inside it with the name
"txtbox"?
You need to go through all the children and find the one with the name.
Try the following:
def all_descendants(w, flags=None):
""" Generator to traverse all descendants of a widget in depth-first
order. Assumes that the widget hierarchy doesn't change during the
traversal. Use flags to only return widgets where widget & flags is
true. If a widget is filtered out, all of its descendants are also
filtered out. """
if not isinstance(w, gtk.Container):
return
for child in w.get_children():
if flags is None or child.flags() & flags:
yield child
for g_kid in all_descendants(child):
yield g_kid
def find_named(parent, name):
for w in all_descendants(parent):
if w.get_name() = name:
return w
return None
entry = find_named(frame, 'txtbox')
You probably do want to make sure that only one widget with the name
'txtbox' is a descendant of frame. gtk does not enforce this for you.
I generally prefer to avoid the recursion and use something like this:
def all_descendants(root):
stack = [root]
while stack:
w = stack.pop()
yield w
if isinstance(w, gtk.Container):
stack.extend(reversed(w.get_children()))
if isinstance(w, gtk.MenuItem):
submenu = w.get_submenu()
if submenu:
stack.append(submenu)
Submenus don't count as children but for most things it's useful to have
them listed in the same way. I would also recommend putting all the
widgets into a dictionary if you'll be doing these lookups often:
def named_widgets(root):
r = {}
for w in all_descendants(root):
name = w.get_name()
if name:
r[name] = w
return r
--
Tim Evans
Applied Research Associates NZ
http://www.aranz.co.nz/
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