Can someone please explain why it is not possible to select the first child
row in the attached program, although there is no problem selecting the
other child rows.
--
Jeffrey Barish
# This test selects particular rows identified by looking at their row.path.
# The select_path statement does not work after testing row.path for equality
# with (8, 0).
import gtk
class SelectRowsTestApp(object):
def __init__(self):
self.window = gtk.Window()
self.window.set_size_request(200, 500)
self.window.connect("destroy", gtk.main_quit)
treestore = gtk.TreeStore(str)
for i in range(9):
treeiter = treestore.append(None, ["Row %d" % i])
treestore.append(treeiter, ["Subrow (8, 0)"])
treestore.append(treeiter, ["Subrow (8, 1)"])
treestore.append(treeiter, ["Subrow (8, 2)"])
treestore.append(None, ["Row 9"])
treeview = gtk.TreeView(treestore)
cell = gtk.CellRendererText()
col = gtk.TreeViewColumn('Text', cell, text=0)
treeview.append_column(col)
treesel = treeview.get_selection()
treesel.set_mode(gtk.SELECTION_MULTIPLE)
self.window.add(treeview)
self.window.show_all()
def select(rows):
for row in rows:
if row[0] in ['Subrow (8, 0)', 'Subrow (8, 1)', 'Subrow (8, 2)']:
if row.path == (8, 0):
print "selecting (8, 0)"
# I get the message above, so I know that I enter this
# clause, but no select_path statement is effective.
treesel.select_path((8, 0))
#treesel.select_path((8, 1))
# But selection works fine after a test for any other row.
if row.path == (8, 1):
print "selecting (8, 1)"
# Selecting a path works fine here, even (8, 0).
#treesel.select_path((8, 0))
treesel.select_path((8, 1))
if row.path == (8, 2):
print "selecting (8, 2)"
treesel.select_path((8, 2))
treeview.expand_row(row.parent.path, False)
select(row.iterchildren())
select(treestore)
def run(self):
self.window.show_all()
gtk.main()
app = SelectRowsTestApp()
app.run()
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