On 12/27/06, Ian Bicking <[EMAIL PROTECTED]> wrote:
Shannon -jj Behrens wrote:
>
> On 12/27/06, Ian Bicking <[EMAIL PROTECTED]> wrote:
>>
>> Shannon -jj Behrens wrote:
>> >
>> > Agreed! Merry Christmas to everyone!
>> >
>> > Here is my gift to you all: write a function that acts like max, but
>> > instead of returning the item in the list, return the index of the
>> > item....
>>
>> Puzzles!
>>
>> def maxindex(seq):
>> return max(zip(seq, itertools.count()))[1]
>
> maxindex([1, 1, 0]) => 1, but I think it should be 0 ;)
Man, that makes it a lot harder...
def maxindex(seq):
return -max(zip(seq, (-i for i in itertools.count())))
Seems like count should take a step argument, then I could just use
itertools.count(0, -1), ala:
def count(start=0, step=1):
while 1:
yield start
start += step
def maxindex(seq):
... return seq.index(max(seq))
...
maxindex([0, 0, 1, 1, -1])
2
I implemented it using a for loop earlier.
Fun,
-jj
--
http://jjinux.blogspot.com/
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