Hi Jordan, The answer is something like (assuming reading from a file):
newb=[float(i) for i in open("stuff.dat").read().split()] alter n. ca, b=newb.pop() spectrum b Hope it helps, Tsjerk On Tue, Jun 16, 2015 at 10:25 AM, Jordan Willis <jwillis0...@gmail.com> wrote: > Hi Tsjerk, > > It seems everyone is pointing to this ( > http://www.pymolwiki.org/index.php/Color#Reassigning_B-Factors_and_Coloring) > which I somehow missed. However, they seem to be altering one residue at a > time like I’m doing. > > > Jordan > > On Jun 15, 2015, at 11:59 PM, Tsjerk Wassenaar <tsje...@gmail.com> wrote: > > Hi Jordan, > > Yes, although I don't have the answer at hand, it has been given on the > user list several times. You can find it in the archives. > > Cheers, > > Tsjerk > On Jun 16, 2015 08:16, "Jordan Willis" <jwillis0...@gmail.com> wrote: > >> Hi, >> >> I have a dictionary that has a bunch of values I want to assign to >> b-factors in order to color by. In my script: >> >> for residue in data: >> cmd.alter(“resi >> {}”.format(residue[‘resnum’]),”b={}”.format(residue[‘value’])) >> >> This executes the alter command for each residue. For some reason, its >> taking forever in my script. Is there something inherently inefficient >> about alter? And is there anyway to fix it? Perhaps, assign a bunch of >> b-factors at once. >> >> Jordan >> >> >> ------------------------------------------------------------------------------ >> >> _______________________________________________ >> PyMOL-users mailing list (PyMOL-users@lists.sourceforge.net) >> Info Page: https://lists.sourceforge.net/lists/listinfo/pymol-users >> Archives: http://www.mail-archive.com/pymol-users@lists.sourceforge.net >> > > -- Tsjerk A. Wassenaar, Ph.D.
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