Hi Jordan,
The answer is something like (assuming reading from a file):
newb=[float(i) for i in open("stuff.dat").read().split()]
alter n. ca, b=newb.pop()
spectrum b
Hope it helps,
Tsjerk
On Tue, Jun 16, 2015 at 10:25 AM, Jordan Willis <jwillis0...@gmail.com>
wrote:
> Hi Tsjerk,
>
> It seems everyone is pointing to this (
> http://www.pymolwiki.org/index.php/Color#Reassigning_B-Factors_and_Coloring)
> which I somehow missed. However, they seem to be altering one residue at a
> time like I’m doing.
>
>
> Jordan
>
> On Jun 15, 2015, at 11:59 PM, Tsjerk Wassenaar <tsje...@gmail.com> wrote:
>
> Hi Jordan,
>
> Yes, although I don't have the answer at hand, it has been given on the
> user list several times. You can find it in the archives.
>
> Cheers,
>
> Tsjerk
> On Jun 16, 2015 08:16, "Jordan Willis" <jwillis0...@gmail.com> wrote:
>
>> Hi,
>>
>> I have a dictionary that has a bunch of values I want to assign to
>> b-factors in order to color by. In my script:
>>
>> for residue in data:
>> cmd.alter(“resi
>> {}”.format(residue[‘resnum’]),”b={}”.format(residue[‘value’]))
>>
>> This executes the alter command for each residue. For some reason, its
>> taking forever in my script. Is there something inherently inefficient
>> about alter? And is there anyway to fix it? Perhaps, assign a bunch of
>> b-factors at once.
>>
>> Jordan
>>
>>
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>>
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>
>
--
Tsjerk A. Wassenaar, Ph.D.
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