On 16/11/10 04:30, Dan Stromberg wrote:
> BTW, it might cause confusion down the road to call something that is
> basically like cpython's bsddb (Berkeley DB) by the name "dbm" in pypy's
> library. In the cpython standard library, "dbm" is an interface to ndbm
> databases. These all provide the same dictionary-like interface to Python
> programs, but have somewhat different API's to C, and pretty different,
> incompatible on-disk representations.
Hi Dan,
I played a bit (veeeery quickly) with dbm on both pypy and cpython, and I'm
not sure I get what you mean when you say that our dbm.py is equivalent to
cpython's bsddb. E.g., I can create a db on cpython and open it from pypy, so
it seems that the two modules are compatible.
Moreover, I checked which libraries the links to. On CPython, it links to
libdb-4.8.so:
viper2 ~ $ ldd /usr/lib/python2.6/lib-dynload/dbm.so
linux-gate.so.1 => (0x00884000)
libdb-4.8.so => /usr/lib/libdb-4.8.so (0x00110000)
libpthread.so.0 => /lib/libpthread.so.0 (0x003de000)
libc.so.6 => /lib/libc.so.6 (0x003f8000)
/lib/ld-linux.so.2 (0x002e0000)
the pypy version first tries to open libdb.so, then libdb-4.5.so. I had to
manually modify it to open version 4.8 (I agree that we should find a more
general way to find it), but apart from that what I can see is that it uses
the same underlying wrapper as CPython.
So, to summarise: could you elaborate a bit more why we should delete dbm.py
from pypy?
ciao,
Anto
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