Hello, is your code actually such a heavy list-copy-through-slicing user ?
This question is independent from pypy's eventual desire to speed this python "idiom", though. I myself was using it, but went to use list(), as that look more natural, to my eyes, but that's a matter of taste anyways, I think... On Mon, Sep 28, 2015 at 3:57 PM, Tuom Larsen <tuom.lar...@gmail.com> wrote: > Dear PyPy developers! > > In CPython, a common idiom to copy a list is to use slice, as in: > > copy = original[:] > > I noticed that under PyPy 2.6.0 it seems quite a bit slower than using > `list` constructor: > > from timeit import timeit > print timeit('b = a[:]', 'a = list(range(100))') # 0.0732719898224 > print timeit('b = list(a)', 'a = list(range(100))') # 0.00285792350769 > > Please, could some comment on what is the preferred way to copy a list > under PyPy? Should I try to avoid the "slice way"? > > Thanks! > _______________________________________________ > pypy-dev mailing list > pypy-dev@python.org > https://mail.python.org/mailman/listinfo/pypy-dev -- Vincent Legoll _______________________________________________ pypy-dev mailing list pypy-dev@python.org https://mail.python.org/mailman/listinfo/pypy-dev