Great! 16 июл. 2017 г. 2:32 ПП пользователь "Maciej Fijalkowski" <fij...@gmail.com> написал:
> Hi Armin > > We ended up (Aleksandr is here at pycon russia) using rffi_platform to > get the exact shape of the structure from the header file. There were > a few bugs how exactly this got mapped, so it ended up being a good > way to do it. > > On Sat, Jul 15, 2017 at 8:02 AM, Armin Rigo <armin.r...@gmail.com> wrote: > > Hi Aleksandr, > > > > On 11 July 2017 at 18:33, Aleksandr Koshkin <tinysnipp...@gmail.com> > wrote: > >> So ok, I have to specify headers containing my structs and somehow push > it > >> to rpython toolchain, if I got you correctly. > >> 0. Why? This structures are already described in the vm file as a bunch > of > >> ffi.CStruct objects. > > > > rffi.CStruct() is used to declare the RPython interface for structs > > that are originally defined in C. > > > > You can use lltype.Struct(), but it's not recommended in your case > > because lltype.Struct() is meant to define structs in RPython where > > you *don't* need a precise C-level struct; for example, > > lltype.Struct() could rename and reorder the fields in C if it is more > > efficient. > > > > We don't have a direct way to declare the struct in RPython but also > > force it to generate exactly the C struct declaration you want, > > because we never needed it. You need to use rffi.CStruct() and write > > the struct in the .h file manually too. > > > >> 1. If I have to, how would I do that, is there any example of embedding > >> rpython into something? > > > > Not really. Look maybe at tests using rpython.rlib.entrypoint, like > > rpython/translator/c/test/test_genc:test_entrypoints. > > > > > > A bientôt, > > > > Armin. >
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