Hans-Peter Jansen schreef:
On Monday 23 November 2009, 15:19:06 Nick Gaens wrote:
Hans-Peter Jansen schreef:
[...]
----------------------------
def __init__(self):
self.server = QtNetwork.QTcpServer(self)
self.server.serverPort = 55555
self.server.newConnection.connect(self.clientConnecting)
self.server.listen() # defaults to QHostAddress.Any
def clientConnecting(self): # used by the "server"
if self.server.hasPendingConnections():
connectingClient = self.server.nextPendingConnection()
connectingClient.readyRead.connect(self.receiveData)
def connectToClient(self, ip): # used by the "client"
socket = QtNetwork.QTcpSocket()
socket.readyRead.connect(self.receiveData)
socket.connectToHost(QtNetwork.QHostAddress(ip), 55555) # ip of
server if socket.waitForConnected(5000):
print "Connected!"
----------------------------
[...]
How odd that I receive this mail *the moment* my code started working
:-P.
I found that the serverPort may not be overwritten.
I removed this assignment:
self.server.serverPort = 55555
Assigning properties this way usually won't work in PyQt (although Phil
tackles this already).
try this:
self.server.listen(QtNetwork.QHostAddress.Any, 55555)
and the clients now can connect to the server w/o any problem.. Downside
is that the port is random..
Pete
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Hmm.. That doesn't seem to work :-S..
self.server.listen(QtNetwork.QHostAddress.Any, 55555):
TypeError: argument 1 of QTcpServer.listen() has an invalid type
How can this be? I've got PyQt4.6.2 on WinXP, Python 2.6.4
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