Hi,
In a Windows XP I've renamed a PyTables file to a name containing the
unicode character \u0140. As this character is not mapped to any key
in my keyboard I used the charmap application to write the name and
then copy and paste. My problem is that I don't know how to open this
file. What I've tried is:
1) pass the python unicode string to the openFile method. It fails:
In [63]: f = tables.openFile(u'para\u0140lels.h5')
---------------------------------------------------------------------------
UnicodeEncodeError Traceback (most recent call last)
C:\Documents and Settings\vmas\Escritorio\tonto\paraig³a\<ipython console> in <m
odule>()
C:\Python25\lib\site-packages\tables\file.pyc in openFile(filename, mode, title,
rootUEP, filters, nodeCacheSize, **kwargs)
239
240 # Finally, create the File instance, and return it
--> 241 return File(path, mode, title, rootUEP, filters, **params)
242
243
C:\Python25\lib\site-packages\tables\hdf5Extension.pyd in tables.hdf5Extension.F
ile.__cinit__()
UnicodeEncodeError: 'ascii' codec can't encode character u'\u0140' in position 4
: ordinal not in range(128)
2) Try to find out the encoded representation of the unicode string and use it
In [65]: sys.getfilesystemencoding()
Out[65]: 'mbcs'
In [66]: fname = u'para\u0140lels.h5'.encode('mbcs')
In [67]: fname
Out[67]: 'para?lels.h5'
In [68]: f = tables.openFile(fname)
---------------------------------------------------------------------------
IOError Traceback (most recent call last)
C:\Documents and Settings\vmas\Escritorio\tonto\paraig³a\<ipython console> in <m
odule>()
C:\Python25\lib\site-packages\tables\file.pyc in openFile(filename, mode, title,
rootUEP, filters, nodeCacheSize, **kwargs)
239
240 # Finally, create the File instance, and return it
--> 241 return File(path, mode, title, rootUEP, filters, **params)
242
243
C:\Python25\lib\site-packages\tables\hdf5Extension.pyd in tables.hdf5Extension.F
ile.__cinit__()
C:\Python25\lib\site-packages\tables\utils.pyc in checkFileAccess(filename, mode
)
145 # The file should be readable.
146 if not os.access(filename, os.F_OK):
--> 147 raise IOError("``%s`` does not exist" % (filename,))
148 if not os.path.isfile(filename):
149 raise IOError("``%s`` is not a regular file" % (filename,))
IOError: ``para?lels.h5`` does not exist
In [69]:
So what have I to do in order to open the file?
TIA
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