Hi Anthony,
> You can use tuple addition to accomplish what you want:
>
> (0,) + data.shape == (0,256,1,2)
>
> Be Well
> Anthony
Thanks! I knew there had to be a better way.
Cheers,
Andre
>
> On Sat, Oct 6, 2012 at 12:42 PM, Andre' Walker-Loud <walksl...@gmail.com>
> wrote:
> Hi All,
>
> I have a bunch of hdf5 files I am using to create one hdf5 file.
> Each individual file has many different pieces of data, and they are all the
> same shape in each file.
>
> I am using createEArray to make the large array in the final file.
>
> if the data files in the individual h5 files are of shape (256,1,2), then I
> have to use
>
> createEArray('/path/','name',tables.floatAtom64(),(0,256,1,2),expectedrows=len(data_files))
>
> if the np array I have grabbed from an individual file to append to my EArray
> is defined as data, is there a way to use data.shape to create the shape of
> my EArray?
>
> In spirit, I want to do something like (0,data.shape) but this does not work.
> I have been scouring the numpy manual to see how to convert
>
> data.shape
> (256,1,2)
>
> to (0,256,1,2)
>
> but failed to figure this out (if I don't know ahead of time the shape of
> data - in which case I can manually reshape).
>
>
> Thanks,
>
> Andre
>
>
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