Feature Requests item #1185121, was opened at 2005-04-18 07:11 Message generated for change (Settings changed) made by rhettinger You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=355470&aid=1185121&group_id=5470
>Category: Python Library >Group: None Status: Open Resolution: None Priority: 5 Submitted By: Jurjen N.E. Bos (jneb) >Assigned to: Raymond Hettinger (rhettinger) Summary: itertools.imerge: merge sequences Initial Comment: (For the itertools library, so Python 2.2 and up) This is a suggested addition to itertools, proposed name imerge. usage: imerge(seq0, seq1, ..., [key=<key function>]) result: imerge assumes the sequences are all in sorted order, and produces a iterator that returns pairs of the form (value, index), where value is a value of one of the sequences, and index is the index number of the given sequence. The output the imerge is in sorted order (taking into account the key function), so that identical values in the sequences will be produced from left to right. The code is surprisingly short, making use of the builtin heap module. (You may disagree with my style of argument handling; feel free to optimize it.) def imerge(*iterlist, **key): """Merge a sequence of sorted iterables. Returns pairs [value, index] where each value comes from iterlist[index], and the pairs are sorted if each of the iterators is sorted. Hint use groupby(imerge(...), operator.itemgetter(0)) to get the items one by one. """ if key.keys() not in ([], ["key"]): raise TypeError, "Excess keyword arguments for imerge" key = key.get("key", lambda x:x) from heapq import heapreplace, heappop #initialize the heap containing (inited, value, index, currentItem, iterator) #this automatically makes sure all iterators are initialized, then run, and finally emptied heap = [(False, None, index, None, iter(iterator)) for index, iterator in enumerate(iterlist)] while heap: inited, item, index, value, iterator = heap[0] if inited: yield value, index try: item = iterator.next() except StopIteration: heappop(heap) else: heapreplace(heap, (True, key(item), index, item, iterator)) If you find this little routine worth its size, please put it into itertools. - Jurjen ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=355470&aid=1185121&group_id=5470 _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com