Bugs item #1167751, was opened at 2005-03-21 09:47 Message generated for change (Comment added) made by nnorwitz You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1167751&group_id=5470
Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Parser/Compiler Group: Python 2.5 >Status: Closed >Resolution: Fixed Priority: 8 Submitted By: John Ehresman (jpe) >Assigned to: Anthony Baxter (anthonybaxter) Summary: Argument genexp corner case Initial Comment: The following raises an unexpected exception; I would expect it to either work or raise a SyntaxError. It seems that the grammar parses it, but the compiler does not do the right thing. >>> def foo(a): pass >>> foo(a = i for i in range(10)) Traceback (most recent call last): File "<stdin>", line 1, in ? NameError: name 'i' is not defined foo(a = (i for i in range(10)) works. ---------------------------------------------------------------------- >Comment By: Neal Norwitz (nnorwitz) Date: 2005-10-20 23:27 Message: Logged In: YES user_id=33168 Checked in as: * Python/graminit.c 2.41 * Lib/test/test_genexps.py 1.10 * Grammar/Grammar 1.55 * Misc/NEWS 1.1392 and 1.1391 Leaving it up to Anthony whether this should be backported. ---------------------------------------------------------------------- Comment By: Nick Coghlan (ncoghlan) Date: 2005-10-11 06:43 Message: Logged In: YES user_id=1038590 The problem is definitely on the parser end though: Py> compiler.parse("foo(x=i for i in range(10))") Module(None, Stmt([Discard(CallFunc(Name('foo'), [Keyword('x', Name('i'))], None, None))])) It's getting to what looks like a valid keyword argument in "x=i" and throwing the rest of it away, when it should be flagging a syntax error (the parser's limited lookahead should be enough to spot the erroneous 'for' keyword and bail out). The problem's actually worse than the OP noted: consider what will happen if there is a variable "i" visible from the location of the function call (e.g. from a list comprehension or for loop in a nested scope). Good luck tracking that one down. . . ---------------------------------------------------------------------- Comment By: Neal Norwitz (nnorwitz) Date: 2005-10-10 21:10 Message: Logged In: YES user_id=33168 I definitely agree this is a big problem. Here's what the code above generates: 2 0 LOAD_GLOBAL 0 (foo) 3 LOAD_CONST 1 ('a') 6 LOAD_GLOBAL 1 (i) 9 CALL_FUNCTION 256 12 POP_TOP 13 LOAD_CONST 0 (None) 16 RETURN_VALUE If I put parens around the genexp, I get: 2 0 LOAD_GLOBAL 0 (foo) 3 LOAD_CONST 1 ('a') 6 LOAD_CONST 2 (<code object <generator expression> at 0x2a960baae8, file "<stdin>", line 2>) 9 MAKE_FUNCTION 0 12 LOAD_GLOBAL 1 (range) 15 LOAD_CONST 3 (10) 18 CALL_FUNCTION 1 21 GET_ITER 22 CALL_FUNCTION 1 25 CALL_FUNCTION 256 28 POP_TOP 29 LOAD_CONST 0 (None) 32 RETURN_VALUE ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1167751&group_id=5470 _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com