Bugs item #1500179, was opened at 2006-06-03 15:32
Message generated for change (Comment added) made by akuchling
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Category: Regular Expressions
Group: Python 2.4
Status: Open
Resolution: None
Priority: 5
Submitted By: Baptiste Lepilleur (blep)
Assigned to: Gustavo Niemeyer (niemeyer)
Summary: re.escape incorrectly escape literal.
Initial Comment:
Using Python 2.4.2.
Here is a small programm excerpt that reproduce the
issue (attached):
---
import re
literal = r'E:\prg\vc'
print 'Expected:', literal
print 'Actual:', re.sub('a', re.escape(literal), 'a' )
assert re.sub('a', re.escape(literal), 'a' ) == literal
---
And the output of the sample:
---
Expected: E:\prg\vc
Actual : E\:\prg\vc
Traceback (most recent call last):
File "re_escape_bug.py", line 5, in ?
assert re.sub('a', re.escape(literal), 'a' ) == literal
AssertionError
---
Looking at regular expression syntax of python
documentation I don't see why ':' is escaped as '\:'.
Baptiste.
----------------------------------------------------------------------
>Comment By: A.M. Kuchling (akuchling)
Date: 2006-06-03 16:27
Message:
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The assertion is wrong, I think. The signature is re.sub(pattern,
replacement,
string), so the assertion is replacing 'a' with re.escape(literal), which is
obviously not going to equal literal.
re.escape() puts a backslash in front of all non-alphanumeric characters; ':'
is
non-alphanumeric, so it will be escaped. The regex parser will ignore
unknown escapes, so \: is the same as : -- the redundant escaping is
harmless.
----------------------------------------------------------------------
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