Bugs item #1574310, was opened at 2006-10-10 09:45
Message generated for change (Comment added) made by ronaldoussoren
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Category: Python Library
Group: Python 2.4
Status: Open
Resolution: None
Priority: 5
Private: No
Submitted By: dtrosset (dtrosset)
Assigned to: Nobody/Anonymous (nobody)
Summary: os.popen with os.close gives error message
Initial Comment:
Given the following code:
import os
child_stdin = os.popen("cat -", "w")
old_stdout = os.dup(1)
os.close(child_stdin.fileno())
print "foo"
os.dup2(old_stdout, 1)
os.close(old_stdout)
I got these different results depending on the version
of python I am using.
$ python2.4 -V
Python 2.4.4c0
$ python2.4 test.py
foo
close failed: [Errno 9] Bad file descriptor
$ python2.3 -V
Python 2.3.5
$ python2.3 test/new/test.py
foo
My .02$ guess is that underlying file descriptor of
child_stdin being closed, when trying to delete this
object, it tries again to close it.
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>Comment By: Ronald Oussoren (ronaldoussoren)
Date: 2006-11-08 08:03
Message:
Logged In: YES
user_id=580910
IMHO this is "don't do that then" territory. You're poking around in the inside
of file objects, you have to be careful if you do that.
BTW. What are you trying to accomplish? If you set sys.stdout to child_stdin
(e.g. "import sys; sys.stdout = child_stdin"), print will write to the
pipe. If you really want to be sure that the C-level variable stdout writes to
the pipe: os.dup2(child_stdout.fileno(), 1). You can then close
child_stdout, but still have to do the 'os.dup(1)' part if you want to restore
the real stdout later on.
----------------------------------------------------------------------
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