Bugs item #1598181, was opened at 2006-11-16 22:40
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Category: Python Library
Group: Python 2.5
Status: Open
Resolution: None
Priority: 5
Private: No
Submitted By: Ralf W. Grosse-Kunstleve (rwgk)
Assigned to: Nobody/Anonymous (nobody)
Summary: subprocess.py: O(N**2) bottleneck
Initial Comment:
subprocess.py (Python 2.5, current SVN, probably all versions) contains this
O(N**2) code:
bytes_written = os.write(self.stdin.fileno(), input[:512])
input = input[bytes_written:]
For large but reasonable "input" the second line is rate limiting. Luckily, it
is very easy to remove this bottleneck. I'll upload a simple patch. Below is a
small script that demonstrates the huge speed difference. The output on my
machine is:
creating input
0.888417959213
slow slicing input
61.1553330421
creating input
0.863168954849
fast slicing input
0.0163860321045
done
The numbers are times in seconds.
This is the source:
import time
import sys
size = 1000000
t0 = time.time()
print "creating input"
input = "\n".join([str(i) for i in xrange(size)])
print time.time()-t0
t0 = time.time()
print "slow slicing input"
n_out_slow = 0
while True:
out = input[:512]
n_out_slow += 1
input = input[512:]
if not input:
break
print time.time()-t0
t0 = time.time()
print "creating input"
input = "\n".join([str(i) for i in xrange(size)])
print time.time()-t0
t0 = time.time()
print "fast slicing input"
n_out_fast = 0
input_done = 0
while True:
out = input[input_done:input_done+512]
n_out_fast += 1
input_done += 512
if input_done >= len(input):
break
print time.time()-t0
assert n_out_fast == n_out_slow
print "done"
----------------------------------------------------------------------
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