Bugs item #1590891, was opened at 2006-11-05 11:54
Message generated for change (Comment added) made by rhettinger
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Category: Python Library
Group: None
>Status: Closed
>Resolution: Fixed
Priority: 5
Private: No
Submitted By: MATSUI Tetsushi (mft)
Assigned to: Raymond Hettinger (rhettinger)
Summary: random.randrange don't return correct value for big number
Initial Comment:
Python 2.4.3 (#1, Oct 3 2006, 00:36:06)
[GCC 4.1.1 (Gentoo 4.1.1-r1)] on linux2
Type "help", "copyright", "credits" or "license" for
more information.
>>> import random
>>> random.randrange(1000000000000,
-100000000000000000000, -200)
267471051174796896L
Obviously, the result is not in the specified range;
1000000000000 < 267471051174796896,
-100000000000000000000 < 267471051174796896
and
(267471051174796896 - 1000000000000) % (-200) != 0.
I'm using 2.3.5 and 2.4.3, and their behaviors are
identical.
I haven't checked about 2.5.
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>Comment By: Raymond Hettinger (rhettinger)
Date: 2006-12-20 01:43
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Thanks for the report.
Fixed in revision 53099.
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Comment By: Armin Rigo (arigo)
Date: 2006-11-08 17:22
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Oups. If the interval is very large, the step is
ignored. Patch attached...
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Comment By: Josiah Carlson (josiahcarlson)
Date: 2006-11-08 11:45
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2.5 has the same behavior.
One workaround (until it gets fixed) is to do the following...
def myrandrange(start, stop, step):
return start + random.randrange((stop-start)//step)*step
random.randrange should change to do some variant of the
above, given sane start, stop, step arguments.
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