New submission from takayuki <takayuki...@star.odn.ne.jp>:
Running the following code shows "2 1 4 3", but in reference manual
http://docs.python.org/reference/expressions.html#expression-lists
the evaluation order described as
{expr1: expr2, expr3: expr4}
def f(i):
print i
return i
{f(1):f(2), f(3):f(4)}
I found some of past discussions about this problem, for example,
http://mail.python.org/pipermail/python-dev/2002-November/030461.html
http://mail.python.org/pipermail/python-dev/2002-November/030458.html
http://bugs.python.org/issue448679
http://svn.python.org/view?view=rev&revision=30148
, but current implementation seems not to reflect these accomplishment.
In present, which behaviour is legal?
----------
components: None
messages: 128482
nosy: takayuki
priority: normal
severity: normal
status: open
title: Evaluation order of dictionary display is different from reference
manual.
versions: Python 2.7
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<http://bugs.python.org/issue11205>
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