Daniel Urban <[email protected]> added the comment:
I found another case, when this is a problem: if there are no **kwargs, but
there are some keyword-only arguments:
>>> def f(*, a, b): pass
...
>>> f(a=1, b=2)
>>>
>>> getcallargs(f, a=1, b=2)
Traceback (most recent call last):
...
TypeError: f() takes no arguments (2 given)
The attached issue11256_3.diff patch also fixes this problem, and adds tests
that would have detected this case.
----------
Added file: http://bugs.python.org/file20930/issue11256_3.diff
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<http://bugs.python.org/issue11256>
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