Terry J. Reedy <[email protected]> added the comment:
You are right, I misinterpreted the meaning of 's' without a count (and opened
#11436 to clarify). However, for the fairly common case where a variable-length
binary block is preceded by a 4 byte *binary* count, one can do something which
is not too bad:
>>> block = b'lsfjdlksaj'
>>> n=len(block)
>>> struct.pack('I%ds'%n, n, block)
b'\n\x00\x00\x00lsfjdlksaj'
If leading blanks are acceptable for your example with count as ascii hex
digits, one can do something that I admit is worse:
>>> struct.pack('10s%ds2s'%n, ('%8x\r\n'%n).encode(), block, b'\r\n')
b' a\r\nlsfjdlksaj\r\n'
Of course, for either of these in isolation, I would probably only use .pack
for the binary conversion and otherwise use '+' or b''.join(...).
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