Bugs item #1715302, was opened at 2007-05-08 16:49
Message generated for change (Comment added) made by alanmcintyre
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Category: Python Library
Group: Python 2.5
Status: Open
Resolution: None
Priority: 5
Private: No
Submitted By: Erik Wickstrom (erikcw)
Assigned to: Nobody/Anonymous (nobody)
Summary: datetime.date won't accept 08 or 09 as valid days.
Initial Comment:
The method won't accept 08 or 09 as valid days, but will accept 07.
Here is my output:
Python 2.5.1c1 (release25-maint, Apr 12 2007, 21:00:25)
[GCC 4.1.2 (Ubuntu 4.1.2-0ubuntu4)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import datetime
>>> t = datetime.date(2007, 05, 07)
>>> print t
2007-05-07
>>> t = datetime.date(2007, 05, 08)
File "<stdin>", line 1
t = datetime.date(2007, 05, 08)
^
SyntaxError: invalid token
>>> t = datetime.date(2007, 05, 09)
File "<stdin>", line 1
t = datetime.date(2007, 05, 09)
^
SyntaxError: invalid token
>>> t = datetime.date(2007, 05, 10)
>>> print t
2007-05-10
>>>
I was able to reproduce this on another machine as well:
Python 2.4.3 (#1, Aug 6 2006, 20:52:01)
[GCC 3.2.2 20030222 (Red Hat Linux 3.2.2-5)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
----------------------------------------------------------------------
Comment By: Alan McIntyre (alanmcintyre)
Date: 2007-05-08 17:24
Message:
Logged In: YES
user_id=1115903
Originator: NO
Recommend closing this as not a bug.
A number with a leading zero is interpreted as octal literal, so trying to
interpret 08 gives an error, since anything bigger than 7 isn't allowed in
octal numbers. For your examples above, you should do this:
t = datetime.date(2007, 5, 8)
t = datetime.date(2007, 5, 9)
and then it works as expected.
----------------------------------------------------------------------
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