Anders Kaseorg <ande...@mit.edu> added the comment:
I guess the desugaring is slightly more complicated in the case where the
original function call already used *args or **kwargs:
f(arg0, …, arg999, *args, k0=v0, …, k999=v999, **kwargs)
becomes something like
f(*((arg0, …, arg999) + args),
**dict({'k0': 'v0', …, 'k999': 'v999'}, **kwargs))
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Python tracker <rep...@bugs.python.org>
<http://bugs.python.org/issue12844>
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