Sumudu Fernando <sumu...@gmail.com> added the comment: >>> tuple(itertools.cycle(enumerate(it)) for it in itertools.count()) ... TypeError: 'int' object is not iterable
That is not what happens in the function, though! That would correspond to doing product(*itertools.count(2010)), but if you try that you won't even get past argument expansion (obviously). Doing product(*xrange(10)) gives the error you're talking about, for example. product(itertools.count(2010)) works perfectly well with the version I posted, though it is a bit silly to do it that way since it produces the same values as count itself (which is what "cartesian product" should do), while saving extra bookkeeping along the way. Anyway, I'm pretty new to python and I don't think this is quite relevant enough to warrant opening a new ticket. I'm happy to leave it here for the education of the next neophyte who stumbles across this idiosyncracy of itertools.product. ---------- _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue10109> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
