Matthew Barnett <[email protected]> added the comment: It appears I was wrong. :-(
The simplest solution in that case is for it to return a _copy_ of the dict. ---------- _______________________________________ Python tracker <[email protected]> <http://bugs.python.org/issue14260> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
