Serhiy Storchaka <[email protected]> added the comment:
As far as I understand, this codec can be implemented in Python. There is no
need to modify the interpreter core.
def decode_cesu8(b):
return re.sub('[\uD800-\uDBFF][\uDC00\DFFF]', lambda m: chr(0x10000 |
((ord(m.group()[0]) & 0x3FF) << 10) | (ord(m.group()[1]) & 0x3FF)),
b.decode('utf-8', 'surrogatepass'))
def encode_cesu8(s):
return re.sub('[\U00010000-\U0010FFFF]', lambda m: chr(0xD800 |
((ord(m.group()) >> 10) & 0x3FF)) + chr(0xDC00 | (ord(m.group() & 0x3FF)),
s).encode('utf-8', 'surrogatepass')
def decode_mutf8(b):
return decode_cesu8(b.replace(b'\xC0\x80', b'\x00'))
def encode_mutf8(s):
return encode_cesu8(s).replace(b'\x00', b'\xC0\x80')
----------
nosy: +storchaka
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<http://bugs.python.org/issue2857>
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