Raymond Hettinger added the comment: This isn't a bug. Writing "dict.fromkeys(xrange(1,48),dict.fromkeys(xrange(1,8),0))" results in the inner expression being evaluated just once and then passed to the outer function call as a fully evaluated argument. As a result, the *same* dictionary is being used over and over again.
People commonly encounter similar issue when they try to create initialized list-of-lists with something like s=[[0]*10] which repeats ten of the *same* lists. Instead they should write something like: s=[[0] for i in range(10)] which creates *distinct* inner lists. For you application, consider using a defaultdict which can call a function as needed to create new, distinct values: d = defaultdict(lambda: dict.fromkeys(xrange(1,8), 0)) ---------- nosy: +rhettinger resolution: -> invalid status: open -> closed __________________________________ Tracker <[EMAIL PROTECTED]> <http://bugs.python.org/issue1288> __________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
