New submission from Julian Berman: As is, as far as I can tell, there's no way to easily compare two AST nodes to see if they have the same children and same fields (recursively).
I'm writing some unit tests for a NodeTransformers, so I've settled for comparing `ast.dump()`s of each, which is kind of dirty, but 1) works and 2) produces reasonable failure messages. (As a side note of what else I've tried, comparing, say, a list of the `iter_child_nodes` is not a good alternative, since the tests I'm writing are making assertions that a given node was not modified, which means they deepcopy the node and then want to assert that the "transformed" node is unchanged.) I don't know the global implications of changing ast.AST.__eq__ to know if that's feasible (hopefully someone will comment on that), but if it isn't, another provided way would be nice. ---------- components: Library (Lib) messages: 170826 nosy: Julian priority: normal severity: normal status: open title: Provide a way to compare AST nodes for equality recursively type: enhancement versions: Python 3.3, Python 3.4 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue15987> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
